What is the selection process for B.Tech and what is the minimum KCET score required at KLE Technological University?
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1 Answer
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KLE Technological University's BTech cutoff is based on the 2023 KCET. For the general category, the minimum cutoff is a rank of 3000–6500. The overall cutoff for the KCET is 683–52546 rank.
KLE Technological University admissions are conducted online through its official website. Admission to all programs is entrance-based. For the BE program, admission is based on the KCET/COMEDK UGET/JEE Main exam.
To be eligible for the B.Tech program, applicants must:
- Have passed PUC (Class 12) with at least 45% of marks.
- Have studied Class 12 with Mathematics, Physics, and Chemistry/Biotechnology/Biology/Computer Science
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No. The official authority does not release mock tests. Candidates need to refer to third party websites for the mock tests.
No. The JEE Mains emphasizes on deep knowledge and quote challenging with negative marking whereas KCET is moderately difficult which emphasizes on direct factual questions with no negative markings.
The difficulty level for mathematics is considered as moderate to difficult and other subjects are considered as easier to moderate.
The exam tests knowledge of 11th and 12th syllabus so it is important to focus on 11th and 12th standard NCERT textbooks which gradually start by practicing previous years papers and appearing for mock examinations.
It is important to give mock tests for candidates appearing for KCET examination as it provides a holistic view and it provides a realistic exam experience also helping the candidates for analysing strengths and working on weaknesses.
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