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What is the TNEA cutoff for Mookambigai College of Engineering (MCE Keeranur)?

0 7 Views | Posted 2 months ago
Asked by Shiksha User

  • 2 Answers

  • V

    Answered by

    VISHAL GUPTA | Contributor-Level 10

    a month ago

    TNEA 2024 Cutoff for MCE Keeranur (OC Category):

    •  BE Electronics & Communication Engineering: 36,323 (Round 2), 190,025 (Round 3)
    •  B.Tech Information Technology: 64,292 (Round 2), 196,024 (Round 3)
    •  BE Computer Science and Engineering: 103,694 - 175,807 (Round 2 & 3)

     

  • K

    Answered by

    Khushi Gupta | Contributor-Level 10

    a month ago

    The TNEA cutoff changes for MCE Keeranur each year based on the students and the scores the students have obtained. For 2024, the rank stands at 36323 - 103694 for the OC category. Below is the cutoff for some specific courses.

    BE Electronics & Communication Engineering: 36323 in Round 2; 190025 in Round 3

    B.TechInformation Technology: 64292 in Round 2; 196024 in Round 3

    BE Computer Science and Engineering: 103694 (Round 2) - 175807 (Round 3)

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