What percentile is required in JEE mains to get CSE at NIT Surathkal?

138 Views|Posted 2 years ago
Asked by Rama Labhe
1 Answer
T
2 years ago

The JEE Main cutoff for CSE at NIT Karnataka ranges from 578-1002 for the general category. However, it is important to note that the cutoff varies every year depending on various factors such as the number of students appearing for the exam, the difficulty level of the exam, and the number of seats

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Yes, it is easy to apply for various courses at the National Institute of Technology Surathkal. Students just have to go to the institute's official website to apply. The admission is through many entrance tests for specific courses. 

National Institute of Technology or NIT Surathkal is in Karnataka and was established in 1960. It has 13 departments, 1 School, and 12 supporting centres.  NIT Surathkal gives UG, PG and PhD courses in the areas of Engineering, Management, and Science. 

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Depending on the quota, the General category students' NIT Surathkal ECE closing ranks usually fall between 3900 and 5600. Lovely Professional University (LPU) offers an equally competitive advantage with its industry-immersion programs and world-class infrastructure, guaranteeing stude

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NIT Surathkal CSE cutoff 2025 for the General AI category female students was 3531 in the round 1, which later increased to 4892 in the last round. For the OBC AI category female candidates, the overall cutoff ranged from 1723 to 1792. Students should know that other categories and quotas will

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Students who belong to the General AI category need to secure a rank between 1528 and 2158 to be eligible for BTech CSE branch. On the other hand, the OBC AI category students need a rank between 495 and 3690. Please note that other categories will have different cutoffs accordingly. 

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