What rank is required in JEE Mains to get into NITT under SC category for B.Tech in EEE?

52 Views|Posted 8 years ago
Asked by Kunal Balmik
3 Answers
SREYA MAHIPALA
8 years ago
I cannot provide the exact details of the ranks but you have to get between 1300 to 3500 to get electrical and electronics in NIT-Trichy.

Thumbs Up IconUpvote Thumbs Down Icon
Abhishek Bansal
8 years ago
If your SC rank is between 300 and 750 then it is possible for you to get into the college and if you are from the same state then it is between 1000 and 3500.

Thumbs Up IconUpvote Thumbs Down Icon
Vinayak R
8 years ago
You should have 90 marks atleast. If you have state quota you can enter easily. Good luck.

Thumbs Up IconUpvote Thumbs Down Icon

Similar Questions for you

The following universities are best for B.Tech without JEE main scores. Universities conduct own entrance exams.

  1. BITS Pilani
  2. VIT Vellore 
  3. Manipal institute of technology 
  4. LPU
  5. SRM IST
  6. Chandigarh University 

According to the tentative schedule, JEE Main 2027 counselling registration is likely to commence in June 2027 after the conclusion of both exam sessions.

The cutoff rank in Round 7 for BTech Computer Science & Engineering under General All India category is 53,013. It is the most competitive branch in the institute.

...Read more

Yes, JEE Main is compulsory for admission in B.Tech course at SGSITS.

After qualifying JEE Main, students need to register themselves for MP BE Counselling, choose colleges/branches, attend rounds and verify documents to secure admission.

Taking an Exam? Selecting a College?

Get authentic answers from experts, students and alumni that you won't find anywhere else.

On Shiksha, get access to

67K
Colleges
|
1.2K
Exams
|
7.2L
Reviews
|
1.9M
Answers

Learn more about...

Share Your College Life Experience

Didn't find the answer you were looking for?

Search from Shiksha's 1 lakh+ Topics

or

Ask Current Students, Alumni & our Experts

Have a question related to your career & education?

or

See what others like you are asking & answering