When will NIT, Surathkal Mangalore release application form for M.Sc admissions? What is the process of admission in 2019?

47 Views|Posted 6 years ago
Asked by Priya Reddy
2 Answers
M
6 years ago
Please visit the institute website for the application availability. Eligibility: Candidate must be a graduate in relevant field from a recognised University. Admission Process Written Test: Eligible candidates need to appear for the Written Aptitude Test conducted by the institute. Merit Screening:

...Read more

Thumbs Up IconUpvote Thumbs Down Icon
Gargi Das
6 years ago
Hi, The university is offering M.Tech and B.Tech, M.Sc in chemistry and physics. You have to appear for entrance. The last date is may 27 to apply. Go to the link there is online application for the same- http://applications.nitk.ac.in/ Regards.

Thumbs Up IconUpvote Thumbs Down Icon

Similar Questions for you

Yes, it is easy to apply for various courses at the National Institute of Technology Surathkal. Students just have to go to the institute's official website to apply. The admission is through many entrance tests for specific courses. 

National Institute of Technology or NIT Surathkal is in Karnataka and was established in 1960. It has 13 departments, 1 School, and 12 supporting centres.  NIT Surathkal gives UG, PG and PhD courses in the areas of Engineering, Management, and Science. 

NIT Surathkal BTech cutoff 2025 was 3934 in round 1 for the General AI category, which later increased to 5316 in last round for the BTech ECE course. Students can refer to the table below to know the overall cutoff range for all other All India categories. 

All India CategoryJEE Main Cutoff Range 2025
General3934 - 5316
OBC1687 - 7933
SC808 - 888
ST459 - 459
EWS599 - 6196

Please note that other quotas, catego

...Read more

NIT Surathkal CSE cutoff 2025 for the General AI category female students was 3531 in the round 1, which later increased to 4892 in the last round. For the OBC AI category female candidates, the overall cutoff ranged from 1723 to 1792. Students should know that other categories and quotas will

...Read more

Students who belong to the General AI category need to secure a rank between 1528 and 2158 to be eligible for BTech CSE branch. On the other hand, the OBC AI category students need a rank between 495 and 3690. Please note that other categories will have different cutoffs accordingly. 

Taking an Exam? Selecting a College?

Get authentic answers from experts, students and alumni that you won't find anywhere else.

On Shiksha, get access to

66K
Colleges
|
1.2K
Exams
|
6.9L
Reviews
|
1.8M
Answers

Share Your College Life Experience

Didn't find the answer you were looking for?

Search from Shiksha's 1 lakh+ Topics

or

Ask Current Students, Alumni & our Experts

Have a question related to your career & education?

or

See what others like you are asking & answering