When will the CSIR NET Result be declared?

The CSIR NET 2025 exam will be conducted on December 18 in two shifts. As per the schedule released, the Mathematical Science exam will be held from 3 pm to 6 pm on Dec 18. 

The CSIR NET 2025 Notification was released on September 25 in the form of PDF at csirnet.nta.nic.in. The notification conists if the important information related to the exam like exam dates, syllabus, pattern of an exam, etc.

The National Testing Agency declare the CSIR NET Cut off. It will be released subject and category-wise. The cut off is prepared on the basis of several factors including difficulty of the exam, reservation norms, number of candidates, etc.

Some of the topics that a candidate can revise in the CSIR NET Chemical Science subject:

Organic Reactive Intermediates: Carbocation, Carbanions, Free Radicals, Benzynes
Stereochemistry: Stereogenicity, Stereoselectivity, Enantioselectivity
Organic Reaction Mechanisms 
Pericyclic Reactions
Structure Determination of Organic Compounds
Asymmetric Synthesis, Determination of Enantiomeric and Diastereomeric Excess
IUPAC Nomenclature
Concepts in Organic Synthesis
Chemistry of Natural Products, etc.

The authority will release the CSIR NET 2025 result for the December session on the official website at csirnet.nta.nic.in. It will contain the name of a candidate, roll number, category, parents' name, Post applied (JRF and Assistant Professor or Assistant Professor Only), subject code, etc.