Which are the best colleges that I can get with 94 marks in CET, 48 in JEE and 71% in 12th?

701 Views|5 Followers|Posted 9 years ago

Asked by Shreyas Jadhav

17 Answers

Sort by:

Answered by

Ankit Kumar | Guide-Level 15

6 years ago

Hi, Visit this link to check colleges based upon your rank: https://www.shiksha.com/b-tech/resources/mhcet-college-predictor.

Upvote

Answered by

Saket Raj Sahu | Guide-Level 15

6 years ago

Just go through this link and fill out the required details: https://www.shiksha.com/college-predictor

Upvote

Answered by

Pradeep Bisht | Scholar-Level 16

6 years ago

Hello, Please use the college predictor tool by Shiksha. This will help you to predict the college according to your rank or percentile. https://www.shiksha.com/college-predictor. Good luck.

Upvote

Answered by

Ravikant Dhurve | Guide-Level 15

6 years ago

You can visit this link: https://www.shiksha.com/college-predictor.

Upvote

Answered by

Rahul Dhurve | Guide-Level 15

6 years ago

You can visit this link: https://www.shiksha.com/college-predictor.

Upvote

Answered by

Srinarayan Prajapati | Guide-Level 15

7 years ago

Hello Please go with this college predictor this will help you to choose the best for you https://www.shiksha.com/college-predictor Thank you.

Upvote

Answered by

Sharath H Aithal | Scholar-Level 17

7 years ago

Hi, Visit this link to check colleges based upon your rank: https://www.shiksha.com/b-tech/resources/mhcet-college-predictor

Upvote

Answered by

Deepak Prajapati | Scholar-Level 16

7 years ago

Please go with this college predictor. This will help you to choose the best for you- https://www.shiksha.com/b-tech/resources/jee-mains-college-predictor Thank you

Upvote

Answered by

Shikhar Singh | Guide-Level 13

7 years ago

As per your JEE score it seems difficult to get any good college over this rank but from your CET score you can get a good college. Check the most possible college name which you can get over this rank. https://www.shiksha.com/b-tech/resources/mhcet-college-predictor.

Upvote