Atlest, How many persentage required for class 12 board CBSE for admission B.Tech computer science

<p>There is no such criteria for getting admission in B tech Computer Science branch but many college wants above 65% for giving admission in college it may vary college to college. However, at the time of placement minimum percentage in 12th should be 60% .&nbsp;</p>

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<p>Most of the universities in India consider <strong>60% to 75%&nbsp;</strong>as minmum percentage in 12th class to take admission in any branch&nbsp;</p><p>Colleges that allow admission through any entrance exam then you get branch depend on your entrance score not through your 12th class score but they have minimum requirements of <strong>60%</strong> <strong>from</strong> <strong>75%</strong> &nbsp;</p><p>Colleges that allow admission through merit list on the basis of 12 th class score then for reputated universities the cut off for branch like <strong>computer</strong>&nbsp;<strong>science&nbsp;</strong>can go higher so it is best to score above <strong>75%</strong></p><p>&nbsp;If you are taking admission through management quata in not such reputated college then minimum score needed in your 12th class is varies from <strong>50% to 70%&nbsp;</strong>Is enough&nbsp;</p><p>&nbsp;</p>

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<p>Hi!</p><p>For admission to B.Tech in <strong>Computer Science</strong> at most universities or colleges in India, the <strong>minimum percentage requirement</strong> for Class 12 (CBSE) generally ranges between <strong>60% to 75%</strong>. However, this can vary depending on the institution and the entrance exam they consider for admission (like JEE Main, state-level exams, or university-specific exams).</p><p>For top colleges or universities, the cutoffs can be higher, especially for popular courses like Computer Science Engineering. It's important to aim for a higher percentage to improve your chances, especially if you are applying through an entrance exam or direct admission based on your Class 12 marks.</p><p>Good luck with your studies and application!&nbsp;</p>

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