Hello my NTA score is 90.19 am I eligible to attend JEE advance I gave the exam on March 17th 2nd shift can I qualify the Mains.

0 13 Views | Posted 3 years ago
Asked by Vishal samraj

  • 1 Answer

  • Shiksha Ask & Answer

    Answered by

    Group Captain Vinayak Deodhar La vie est faite pour vivre pas pour stresser | Scholar-Level 18

    3 years ago
    Hello Vishal Samraj, if you are from general category then I am afraid that you may not become eligible to appear for JEE Advanced if we consider last year's cutoff which was 90.3. I am attaching list of cutoffs for different categories of last year. Cut-off for JEE Advance
    Candidates having at least 90.3765335 percentile will be eligible to appear for JEE Advanced. For EWS students the cut-off is 70.2435518, for OBC it is 72.8887969, SC - 50.1760245, ST - 39.0696101, PwD - 0.06185224
    In view of this I would strongly advise you to appear for the remaining two sessions of JEE Mains examination to improve your percentile. Best wishes to yo
    ...more

Get authentic answers from experts, students and alumni that you won't find anywhere else

Sign Up on Shiksha

On Shiksha, get access to

  • 63k Colleges
  • 963 Exams
  • 610k Reviews
  • -50000 Answers

Share Your College Life Experience

Didn't find the answer you were looking for?

Search from Shiksha's 1 lakh+ Topics

or

Ask Current Students, Alumni & our Experts

×
×

This website uses Cookies and related technologies for the site to function correctly and securely, improve & personalise your browsing experience, analyse traffic, and support our marketing efforts and serve the Core Purpose. By continuing to browse the site, you agree to Privacy Policy and Cookie Policy.

Need guidance on career and education? Ask our experts

Characters 0/140

The Answer must contain atleast 20 characters.

Add more details

Characters 0/300

The Answer must contain atleast 20 characters.

Keep it short & simple. Type complete word. Avoid abusive language. Next

Your Question

Edit

Add relevant tags to get quick responses. Cancel Post