How many marks are required in GUJCET for B.E. in Computer Engineering at Sardar Vallabhbhai Patel Institute of Technology?

<p>Sardar Vallabhbhai Patel Institute of Technology GUJCET Cutoff 2024 was released for Round 1. The Cutoff was released for different categories under the HS Quota. The Cutoff ranged between <strong>7012 and 38600</strong>, for the General HS category candidates. The Cutoff for B.E. in Computer Engineering closed at <strong>7012</strong>, for the General HS category candidates.&nbsp;</p><p>For the OBC HS category candidates, the Cutoff for BE in Computer Engineering closed at <strong>13610</strong>. For the ST and the SC category candidates, the Cutoff for CE closed at <strong>35905</strong> and <strong>19521</strong>, respectively.&nbsp;</p><p>For the PWD category candidates, the Cutoff closed at <strong>4843</strong> for BE in CE.&nbsp;</p><p>For the EWS category candidates, the Cutoff closed at <strong>7848&nbsp;</strong>to secure a seat in Computer Engineering at Sardar Vallabhbhai Patel Institute of Technology.&nbsp;</p><p>&nbsp;</p>

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