0.01 moles of a weak acid HA (Ka = 2.0 *10-6) is dissolved in 1.0 L of 0.1 M HCl solution. The degree of dissociation of HA is _______ *10-5. (Round off to the nearest integer).
[Neglect volume change on adding HA. Assume degree of dissociation <<1]
0.01 moles of a weak acid HA (Ka = 2.0 *10-6) is dissolved in 1.0 L of 0.1 M HCl solution. The degree of dissociation of HA is _______ *10-5. (Round off to the nearest integer).
[Neglect volume change on adding HA. Assume degree of dissociation <<1]
For the weak acid HA in the presence of strong acid HCl:
Ka = [ (Cα + 0.1) * Cα] / [C (1-α)] ≈ (0.1 * 10? ²α) / 10? ² = 0.1α
Given Ka = 2 * 10?
2 * 10? = 10? ¹ * α
α = 2 * 10?
Ans = 2
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Chemistry Ncert Solutions Class 11th 2023
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