Ask & Answer Question

Chemical Equilibrium Chemistry Class 11th Equilibrium

A(g) ->B(g) + $\frac{1}{2}$ C(g)

In the about reaction, the correct relation between K_p, a and equilibrium pressure (p) is

Option 1 -

$K_{p} = \frac{α^{\frac{1}{2}} 2 p^{\frac{1}{2}}}{{(2 + α)}^{\frac{1}{2}}}$

Option 2 -

$K_{p} = \frac{α^{\frac{1}{2}} 2 p^{\frac{3}{2}}}{{(2 + α)}^{\frac{3}{2}}}$

Option 3 -

$K_{p} = \frac{α^{\frac{1}{2}} 2 p^{\frac{1}{2}}}{{(2 + α)}^{\frac{3}{2}}}$

Option 4 -

$K_{p} = \frac{α^{\frac{3}{2}} p^{\frac{1}{2}}}{{(2 + α)}^{\frac{1}{2}} (1 - α)}$

2 Views | Posted a month ago

Asked by Shiksha User

1 Answer

Answered by

alok kumar singh | Contributor-Level 10

a month ago

Correct Option - 4

Detailed Solution:

A(g) ->B(g) + $\frac{1}{2}$ (g)

Initial moles n 0 0

Eqb. moles n(1 – a) $\frac{n α}{2}$ n_a

total moles = $n (1 + \frac{α}{2})$

Eqb. pressure $\frac{(1 - α) p}{1 + \frac{α}{2}}$ $\frac{α p}{1 + \frac{α}{2}}$ $\frac{(\frac{α}{2}) p}{1 + \frac{α}{2}}$

$\frac{K_{p} = \frac{α p}{(1 + \frac{α}{2})} \times {[\frac{α p}{(2 + α)}]}^{\frac{1}{2}}}{\frac{(1 + α) p}{1 + \frac{α}{2}}}$

$K_{p} = \frac{α^{\frac{3}{2}} p^{\frac{1}{2}}}{{(2 + α)}^{\frac{1}{2}} (1 - α)}$

...more

A(g) ->B(g) + $\frac{1}{2}$ (g)

Initial moles n 0 0

Eqb. moles n(1 – a) $\frac{n α}{2}$ n_a

total moles = $n (1 + \frac{α}{2})$

Eqb. pressure $\frac{(1 - α) p}{1 + \frac{α}{2}}$ $\frac{α p}{1 + \frac{α}{2}}$ $\frac{(\frac{α}{2}) p}{1 + \frac{α}{2}}$

$\frac{K_{p} = \frac{α p}{(1 + \frac{α}{2})} \times {[\frac{α p}{(2 + α)}]}^{\frac{1}{2}}}{\frac{(1 + α) p}{1 + \frac{α}{2}}}$

$K_{p} = \frac{α^{\frac{3}{2}} p^{\frac{1}{2}}}{{(2 + α)}^{\frac{1}{2}} (1 - α)}$

less

A(g) ->B(g) + <math> <mrow> <mfrac> <mrow> <mn>1</mn> </mrow> <mrow> <mn>2</mn> </mrow> </mfrac> </mrow> </math> (g)Initial moles             n                         0             0Eqb. moles               n(1 – a)   <math> <mrow> <mfrac> <mrow> <mi>n</mi> <mi>α</mi> </mrow> <mrow> <mn>2</mn> </mrow> </mfrac> </mrow> </math>           na            total moles =   <math> <mrow> <mi>n</mi> <mrow> <mo>(</mo> <mrow> <mn>1</mn> <mo>+</mo> <mfrac> <mrow> <mi>α</mi> </mrow> <mrow> <mn>2</mn> </mrow> </mfrac> </mrow> <mo>)</mo> </mrow> </mrow> </math> Eqb. pressure   <math> <mrow> <mfrac> <mrow> <mrow> <mo>(</mo> <mrow> <mn>1</mn> <mo>−</mo> <mi>α</mi> </mrow> <mo>)</mo> </mrow> <mi>p</mi> </mrow> <mrow> <mn>1</mn> <mo>+</mo> <mfrac> <mrow> <mi>α</mi> </mrow> <mrow> <mn>2</mn> </mrow> </mfrac> </mrow> </mfrac> </mrow> </math> <math> <mrow> <mfrac> <mrow> <mi>α</mi> <mi>p</mi> </mrow> <mrow> <mn>1</mn> <mo>+</mo> <mfrac> <mrow> <mi>α</mi> </mrow> <mrow> <mn>2</mn> </mrow> </mfrac> </mrow> </mfrac> </mrow> </math> <math> <mrow> <mfrac> <mrow> <mrow> <mo>(</mo> <mrow> <mfrac> <mrow> <mi>α</mi> </mrow> <mrow> <mn>2</mn> </mrow> </mfrac> </mrow> <mo>)</mo> </mrow> <mi>p</mi> </mrow> <mrow> <mn>1</mn> <mo>+</mo> <mfrac> <mrow> <mi>α</mi> </mrow> <mrow> <mn>2</mn> </mrow> </mfrac> </mrow> </mfrac> </mrow> </math> <math> <mrow> <mfrac> <mrow> <msub> <mrow> <mi>K</mi> </mrow> <mrow> <mi>p</mi> </mrow> </msub> <mo>=</mo> <mfrac> <mrow> <mi>α</mi> <mi>p</mi> </mrow> <mrow> <mrow> <mo>(</mo> <mrow> <mn>1</mn> <mo>+</mo> <mfrac> <mrow> <mi>α</mi> </mrow> <mrow> <mn>2</mn> </mrow> </mfrac> </mrow> <mo>)</mo> </mrow> </mrow> </mfrac> <mo>×</mo> <msup> <mrow> <mrow> <mo>[</mo> <mrow> <mfrac> <mrow> <mi>α</mi> <mi>p</mi> </mrow> <mrow> <mrow> <mo>(</mo> <mrow> <mn>2</mn> <mo>+</mo> <mi>α</mi> </mrow> <mo>)</mo> </mrow> </mrow> </mfrac> </mrow> <mo>]</mo> </mrow> </mrow> <mrow> <mfrac> <mrow> <mn>1</mn> </mrow> <mrow> <mn>2</mn> </mrow> </mfrac> </mrow> </msup> </mrow> <mrow> <mfrac> <mrow> <mrow> <mo>(</mo> <mrow> <mn>1</mn> <mo>+</mo> <mi>α</mi> </mrow> <mo>)</mo> </mrow> <mi>p</mi> </mrow> <mrow> <mn>1</mn> <mo>+</mo> <mfrac> <mrow> <mi>α</mi> </mrow> <mrow> <mn>2</mn> </mrow> </mfrac> </mrow> </mfrac> </mrow> </mfrac> </mrow> </math> <math> <mrow> <msub> <mrow> <mi>K</mi> </mrow> <mrow> <mi>p</mi> </mrow> </msub> <mo>=</mo> <mfrac> <mrow> <msup> <mrow> <mi>α</mi> </mrow> <mrow> <mfrac bevelled="true"> <mrow> <mn>3</mn> </mrow> <mrow> <mn>2</mn> </mrow> </mfrac> </mrow> </msup> <mtext> </mtext> <msup> <mrow> <mi>p</mi> </mrow> <mrow> <mfrac bevelled="true"> <mrow> <mn>1</mn> </mrow> <mrow> <mn>2</mn> </mrow> </mfrac> </mrow> </msup> </mrow> <mrow> <msup> <mrow> <mrow> <mo>(</mo> <mrow> <mn>2</mn> <mo>+</mo> <mi>α</mi> </mrow> <mo>)</mo> </mrow> </mrow> <mrow> <mfrac bevelled="true"> <mrow> <mn>1</mn> </mrow> <mrow> <mn>2</mn> </mrow> </mfrac> </mrow> </msup> <mrow> <mo>(</mo> <mrow> <mn>1</mn> <mo>−</mo> <mi>α</mi> </mrow> <mo>)</mo> </mrow> </mrow> </mfrac> </mrow> </math>

0 Upvotes 0 Downvotes

A(g) ->B(g) + $\frac{1}{2}$ C(g)

In the about reaction, the correct relation between K_p, a and equilibrium pressure (p) is

1 Answer

Similar Questions for you

Learn more about...

Most viewed information

Share Your College Life Experience

Didn't find the answer you were looking for?

Need guidance on career and education? Ask our experts

Your Question

A(g) ->B(g) + 1 2 C(g) In the about reaction, the correct relation between Kp, a and equilibrium pressure (p) is

1 Answer

Similar Questions for you

Learn more about...

Most viewed information

Share Your College Life Experience

Didn't find the answer you were looking for?

Need guidance on career and education? Ask our experts

Your Question

A(g) ->B(g) + $\frac{1}{2}$ C(g)

In the about reaction, the correct relation between K_p, a and equilibrium pressure (p) is