3O₂(g) ⇌ 2O₃(g)
For the above reaction at 298 K, Kc is found to be 3.0 * 10⁻⁵⁹. If the concentration of O₂ at equilibrium is 0.040M the then concentration of O₃ in M is:
3O₂(g) ⇌ 2O₃(g)
For the above reaction at 298 K, Kc is found to be 3.0 * 10⁻⁵⁹. If the concentration of O₂ at equilibrium is 0.040M the then concentration of O₃ in M is:
3O? 2O?
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0.01 M NaOH,
M = 1 * 10-2

pOH = 2
pH = 2
Kp = Kc (RT)Dng
36 * 10–2 = Kc (0.0821 * 300)–1
Kc = 0.36 * 0.0821 * 300 = 8.86 » 9
A(g) ->B(g) + (g)
Initial moles n 0 &nbs
On increasing pressure, equilibrium moves in that direction where number of gaseous moles decreases.
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