A 2.0g sample containing MnO2 is treated with HCl liberating Cl2. The Cl2 gas is passed into a solution of Kl and 60.0mL of 0.1M Na2S2O3 is required to titrate the liberated iodine. The percentage of MnO2 in the sample is_______. (Nearest integer)

 [Atomic masses (in u) Mn = 55; Cl = 35.5; O = 16, I = 127, Na = 23, K = 39, S = 32]

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R
4 months ago

M n O 2 + 4 H C l M n C l 2 + C l 2 + 2 H 2 O

C l 2 + 2 K l 2 K C l + I 2 I 2 + 2 N a 2 S 2 O 3 2 N a l + N a 2 S 4 O 6

Here, meq of MnO2 = meq of Na2S4O6

w E * 1 0 0 0 = M * n f a c t o r * V

w 8 7 / 2 * 1 0 0 0 = 0 . 1 * 1 * 6 0

Mass of MnO2 in sample = 0.261 g

Percentage of MnO2 in sample = 0 . 2 6 1 2 * 1 0 0  

 = 13.05%

 

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Chemistry NCERT Exemplar Solutions Class 12th Chapter Seven 2025

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