A body of mass M is rotating in a vertical circle of radius r with critical speed. The difference in its kinetic energy at the top and the bottom is
A body of mass M is rotating in a vertical circle of radius r with critical speed. The difference in its kinetic energy at the top and the bottom is
Option 1 - <p>2 Mgr</p>
Option 2 - <p>4 Mgr</p>
Option 3 - <p>6 Mgr</p>
Option 4 - <p>3 Mgr</p>
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4 months ago
Correct Option - 1
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CH3COOH + NaOH → CH3COONa + H2O
ΔH = –50.6 kJ/mol
NaOH + SA [HCl] → NaCl + H2O
ΔH = –55.9 kJ/mol
the value of ΔH for ionisation of CH3COOH
⇒ ΔH = +55.9 – 50.6
5.3 kJ/mol
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