A certain orbital has no angular nodes and two radial nodes. The orbital is:
A certain orbital has no angular nodes and two radial nodes. The orbital is:
Quantum Numbers and Orbitals:
o Total Node = n - 1 (l => Azimuthal Q.N)
o Radial Node = n - l - 1
o Angular Node: l
o If Angular node = 0, then l = 0, i.e., S orbital.
o If Radial nodes = 2, then n - l - 1 = 2.
o Substituting l = 0 gives n - 0 - 1 = 2, so n = 3.
o Therefore, the orbital is 3s
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CH3COOH + NaOH → CH3COONa + H2O
ΔH = –50.6 kJ/mol
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the value of ΔH for ionisation of CH3COOH
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