A particle of mass m with an initial velocity ui + 2uĵ collides with a particle of mass 3m at rest. After collision, the two particles stick together and the combined particle moves with a velocity vî + v'ĵ. Which of the following is incorrect?

Option 1 - <p>v = v'/2<br><!-- [if !supportLineBreakNewLine]--><br><!--[endif]--></p>
Option 2 - <p>v = 2v'<br><!-- [if !supportLineBreakNewLine]--><br><!--[endif]--></p>
Option 3 - <p>v = u/4<br><!-- [if !supportLineBreakNewLine]--><br><!--[endif]--></p>
Option 4 - <p>v'=u/2</p>
3 Views|Posted 5 months ago
Asked by Shiksha User
1 Answer
V
5 months ago
Correct Option - 2
Detailed Solution:

Applying conservation of momentum, m (ui + 2uj) + 3m (0) = 4m (vi +vj)
⇒ v = u / 4 and v' = u / 2

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Physics Laws of Motion 2025

Physics Laws of Motion 2025

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