A rod AB moves with a uniform velocity v in a uniform magnetic field as shown in figure then :-
A rod AB moves with a uniform velocity v in a uniform magnetic field as shown in figure then :-
Option 1 - <p>The rod becomes electrically charged.</p>
Option 2 - <p>The end A becomes positively charged.</p>
Option 3 - <p>The end B becomes positively charged.</p>
Option 4 - <p>The rod becomes hot because of joule heating.</p>
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Correct Option - 3
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Bv = B sin 60°
->
M = φ? /I? = (B? A? )/I? = [ (μ? I? /2R? )πR? ²]/I?
[Diagram of two concentric coils]
M = (μ? πR? ²)/ (2R? )
M ∝ R? ²/R?
(A) The magnet's entry
R =
L = 2 mH
E = 9V
Just after the switch ‘S’ is closed, the inductor acts as open circuit.
PR = l2R
=> 640 = (8)2 R
R =
from (i) 64 =
L = 2H
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Physics Ncert Solutions Class 12th 2023
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