A solid circular disc (m, R) translates with V? and rotates with ω? = 2V0/R at t = 0. Because of friction, pure rolling starts at t = t0. The coefficient of friction is μ. Find t0.
A solid circular disc (m, R) translates with V? and rotates with ω? = 2V0/R at t = 0. Because of friction, pure rolling starts at t = t0. The coefficient of friction is μ. Find t0.
Option 1 - <p>V₀/(3μg)<br><!-- [if !supportLineBreakNewLine]--><br><!--[endif]--></p>
Option 2 - <p>4V₀/(3μg)<br><!-- [if !supportLineBreakNewLine]--><br><!--[endif]--></p>
Option 3 - <p>2V₀/(3μg)<br><!-- [if !supportLineBreakNewLine]--><br><!--[endif]--></p>
Option 4 - <p>V₀/(μg)</p>
30 Views|Posted 5 months ago
Asked by Shiksha User
1 Answer
V
Answered by
5 months ago
Correct Option - 1
Detailed Solution:
a = fr/m
∴ V = V? + at? = V? + (fr/m)t?
and α = 2Rfr/mR² = 2fr/mR
∴ ω = ω? - (2fr/mR)t?
∴ V = ωR ∴ v? + (fr/m)t? = ω? R - (2fr/m)t?
= (3fr/m)t? = V? = (fr/m)et?
∴ V = V? + V? /3 = 4V? /3
t? = mV? / (3μmg)
= V? /3μg
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