In a rocket, fuel burns at the rate of 1 $k g / s .$ This fuel is ejected from the rocket with a velocity of 60 $k m / s$ . This exerts a force on the rocket equal to

Option 1 - 6000 N

Option 2 - 60000N

Option 3 - 60N

Option 4 - 600N

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Answered by

Raj Pandey | Contributor-Level 9

4 months ago

Correct Option - 2

Detailed Solution:

Rate of burning of fuel $(\frac{d m}{d t}) = 1 k g / s$ and velocity of ejected fuel

$(v) = 60 k m / s$

$= 60 * 1 0^{3} m / s .$

Forcev = Rate of change of momentum

$= \frac{d p}{d t} = \frac{d (m ν)}{d t} = v \frac{d m}{d t} = (60 * 1 0^{3}) * 1$

$= 60000$ N.

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In a rocket, fuel burns at the rate of 1 k g / s . This fuel is ejected from the rocket with a velocity of 60 k m / s . This exerts a force on the rocket equal to

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