Class 11th Structure of Atom Chemistry

For Rb(37) which of the following set of quantum numbers are correct for valence electron?

Option 1 - <p><span lang="EN-IN">5, 0, 0, + </span><span class="mathml" contenteditable="false"> <math> <mrow> <mfrac> <mrow> <mn>1</mn> </mrow> <mrow> <mn>2</mn> </mrow> </mfrac> </mrow> </math> </span></p>

Option 2 - <p><span lang="EN-IN">5, 0, 1, –<span class="mathml" contenteditable="false"> <math> <mrow> <mfrac> <mrow> <mn>1</mn> </mrow> <mrow> <mn>2</mn> </mrow> </mfrac> </mrow> </math> </span> </span></p>

Option 3 - <p><span lang="EN-IN">5, 0, 1 + </span><span lang="EN-IN"><span contenteditable="false"> <math> <mrow> <mfrac> <mrow> <mn>1</mn> </mrow> <mrow> <mn>2</mn> </mrow> </mfrac> </mrow> </math> </span></span></p>

Option 4 - <p><span lang="EN-IN">5, 1, 1 + </span><span lang="EN-IN"><span contenteditable="false"> <math> <mrow> <mfrac> <mrow> <mn>1</mn> </mrow> <mrow> <mn>2</mn> </mrow> </mfrac> </mrow> </math> </span></span></p>

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Alok Kumar Singh | Contributor-Level 10

4 months ago

Correct Option - 1

Detailed Solution:

₃₇Rb = 1s² 2s² 2p⁶ 3s² 3p⁶ 3d¹⁰ 4s² 4p⁶ 5s¹

Last electron enters in 5s subshell

Value of quantum numbers

n = 5, l = 0, m = 0, s = $\pm \frac{1}{2}$

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