The number of moles of K2Cr2O7 that will be needed to react with one mole of nitrite ion in acidic solution is
The number of moles of K2Cr2O7 that will be needed to react with one mole of nitrite ion in acidic solution is
Option 1 - <p><span lang="EN-IN">2/3 </span></p>
Option 2 - <p><span lang="EN-IN">1/3 </span></p>
Option 3 - <p><span lang="EN-IN">1/6 </span></p>
Option 4 - <p><span lang="EN-IN">½</span></p>
4 Views|Posted 4 months ago
Asked by Shiksha User
1 Answer
A
Answered by
4 months ago
Correct Option - 2
Detailed Solution:
Kindly go through the solution
Similar Questions for you
CH3COOH + NaOH → CH3COONa + H2O
ΔH = –50.6 kJ/mol
NaOH + SA [HCl] → NaCl + H2O
ΔH = –55.9 kJ/mol
the value of ΔH for ionisation of CH3COOH
⇒ ΔH = +55.9 – 50.6
5.3 kJ/mol
Kindly consider the solution
Fact.
Kindly go through the solution
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else.
On Shiksha, get access to
66K
Colleges
|
1.2K
Exams
|
6.9L
Reviews
|
1.8M
Answers
Learn more about...

Chemistry Redox Reactions 2025
View Exam DetailsMost viewed information
SummaryDidn't find the answer you were looking for?
Search from Shiksha's 1 lakh+ Topics
or
Ask Current Students, Alumni & our Experts
Have a question related to your career & education?
or
See what others like you are asking & answering



