The orbital angular momentum of 3d electron is
The orbital angular momentum of 3d electron is
Option 1 - <p>√2h</p>
Option 2 - <p>√6h</p>
Option 3 - <p>√5h</p>
Option 4 - <p>√3h</p>
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4 months ago
Correct Option - 2
Detailed Solution:
Orbital angular momentum
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CH3COOH + NaOH → CH3COONa + H2O
ΔH = –50.6 kJ/mol
NaOH + SA [HCl] → NaCl + H2O
ΔH = –55.9 kJ/mol
the value of ΔH for ionisation of CH3COOH
⇒ ΔH = +55.9 – 50.6
5.3 kJ/mol
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