Two radioactive substances X and Y originally have N1 and N2 nuclei respectively. Half life of X is half of the life of Y. After three half lives of Y, number of nuclei of both are equal.
The ratio
will be equal to:
Two radioactive substances X and Y originally have N1 and N2 nuclei respectively. Half life of X is half of the life of Y. After three half lives of Y, number of nuclei of both are equal.
The ratio will be equal to:
Option 1 -
Option 2 -
Option 3 -
Option 4 -
-
1 Answer
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Correct Option - 2
Detailed Solution:Number of half lives of Y = 3
Number of half lives of X = 6 [As half life of X is half of that of Y].
Similar Questions for you
N = N0e–λt
->t = λN = N0/e
So number of nuclei decayed = N0 – N
= N0 (1- 1/e)
Density of nuclei is order of 1017 kg m–3.
Density of nuclei is order of 1017 kg m-3.
According to Nuclear activity, we can write
Time required = 4 ×
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