10.7 Which alkyl halide from the following pairs would you expect to react more rapidly by an SN2 mechanism? Explain your answer.

In S_N2 Reaction, the product will be formed in a single step with no intermediates. Nucleophile attack will be easier for simple halides than hindered haloalkanes. Therefore,

1. Bromobutane (1°)reacts faster than 2-Bromobutane (2°)
2. 2-Bromobutane (2°) reacts faster than 2-Bromo-2-methylpropane or tert-Butyl bromide (3°) 1-Bromo-3-methyl butane reacts faster than the 1-Bromo-2-methyl bu
3. tane as the former is less hindered with respect to leaving halide than the later which is more hindered comparatively

<p><picture><img src="https://images.shiksha.com/mediadata/images/articles/1690436395phpWUrh11.jpeg" alt="" width="329" height="198"></picture></p><p>In S_N2 Reaction, the product will be formed in a single step with no intermediates. Nucleophile attack will be easier for simple halides than hindered haloalkanes. Therefore, </p><div><div><picture><source srcset="https://images.shiksha.com/mediadata/images/articles/1690436423phpFfdZ6c_480x360.jpeg" media=" (max-width: 500px)"><img src="https://images.shiksha.com/mediadata/images/articles/1690436423phpFfdZ6c.jpeg" alt="" width="510" height="118"></picture></div></div><ol><li>Bromobutane (1°)reacts faster than 2-Bromobutane (2°)</li><li>2-Bromobutane (2°) reacts faster than 2-Bromo-2-methylpropane or tert-Butyl bromide (3°)&nbsp;1-Bromo-3-methyl butane reacts faster than the 1-Bromo-2-methyl bu</li><li>tane as the former is less hindered with respect to leaving halide than the later which is more hindered comparatively</li></ol>

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