0.25 M solution of pyridinium chloride C₅H₆N⁺Cl⁻ was found to have a pH of 2.699. if the value of Kₑ of pyridine C₅H₅N is a * 10⁻¹⁰, then the value of a is (given, 10⁻².⁶⁹⁹ = 2 * 10⁻³)

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5 months ago

BCl → B? + Cl?
B? + H? O? BOH + H? , K? = K? /K?
0.25 – –
(0.25 – x) x
Given, pH = 2.7 = [H? ] = 2 * 10? ³
∴ x²/ (0.25) = (10? ¹? )/K?
= 4 * 10? * 4 * K? = 10? ¹?
= K? = (1/16) * 10? = 6.25 * 10? ¹?

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Chemistry Chemical Equilibrium 2025

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