1.18 An element with molar mass 2.7×10-2 kg mol-1 forms a cubic unit cell with edge length 405 pm. If its density is 2.7×103 kg m-3, what is the nature of the cubic unit cell?
1.18 An element with molar mass 2.7×10-2 kg mol-1 forms a cubic unit cell with edge length 405 pm. If its density is 2.7×103 kg m-3, what is the nature of the cubic unit cell?
-
1 Answer
-
1.18 Molar mass of the element = 2.7*10-2 kg mol-1
Edge length, a = 405 pm
Density, d = 2.7*103 kg m-3
Using the formula, d=? *? / ? 3NA
Putting the values given at their appropriate place, we get(2.7 X 103 )X (405 X 10-12)3 X 6.022 X 10 / 2.7*10-2 = 3.99 which is approximately equal to 4
Therefore, it is an fcc unit cell
Similar Questions for you
ΔG° = –RT * 2.303 log K
–nFE° = +RT * 2.303 log K
2 * 96500 * 0.295 = 8.314 * 298 * 2.303 log10 K
10 = log10 K = 1010
It has chiral centre and differently di substituted double bonded carbon atoms.
For FCC lattice
Packing efficiency = 
CsCl has BCC structure in which Cl– is present at corners of cube and Cs+ at body centre
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else
Sign Up on ShikshaOn Shiksha, get access to
- 65k Colleges
- 1.2k Exams
- 678k Reviews
- 1800k Answers

