1.80g of solute A was dissolved in 62.5cm3 of ethanol and freezing point of the solution was found to be 155.1 K . The molar mass of solute A is __________g mol-1.

[Given: Freezing point of ethanol is 156.0 K. Density of ethanol is 0.80 g cm-3. Freezing point depression constant of ethanol is 2.00 K kg mol-1]

2 Views|Posted 8 months ago
Asked by Shiksha User
1 Answer
A
8 months ago

Δ T f = K f * m  

( 1 5 6 1 5 5 . 1 ) = 2 * 1 . 8 M W * 1 0 0 0 ( 6 2 . 5 * 0 . 8 )                

  0.9 =   2 * 1 . 8 * 1 0 0 0 M W * 5 0


M W = 8 0 g m / m o l      

Thumbs Up IconUpvote Thumbs Down Icon

Similar Questions for you

ΔG° = –RT * 2.303 log K

–nFE° = +RT * 2.303 log K

2 * 96500 * 0.295 = 8.314 * 298 * 2.303 log10 K

10 = log10 K = 1010

It has chiral centre and differently di substituted double bonded carbon atoms.

Taking an Exam? Selecting a College?

Get authentic answers from experts, students and alumni that you won't find anywhere else.

On Shiksha, get access to

66K
Colleges
|
1.2K
Exams
|
6.9L
Reviews
|
1.8M
Answers

Learn more about...

Chemistry Solutions 2025

Chemistry Solutions 2025

View Exam Details

Most viewed information

Summary

Share Your College Life Experience

Didn't find the answer you were looking for?

Search from Shiksha's 1 lakh+ Topics

or

Ask Current Students, Alumni & our Experts

Have a question related to your career & education?

or

See what others like you are asking & answering