1 kg on 0.75 molal aqueous solution of sucrose can be cooled up to -4°C before freezing. The amount of ice (in g) that will be separated out is__________. (Nearest integer)

[Given : Kf(H2O) = 1.86K kg mol-1]

0 79 Views | Posted 2 months ago
Asked by Shiksha User

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    Answered by

    Vishal Baghel | Contributor-Level 10

    2 months ago

    Let mass of water initially = x gram

    Mass of sucrose = (1000 – x) gram

    Mole of sucrose = 1 0 0 0 x 3 4 2 m o l

    ? 0.75 molal Þ 0.75 mole solute in 1 kg of solvent

    0 . 7 5 = ( 1 0 0 0 x ) / 3 4 2 x / 1 0 0 0 [ m o l a l i t y = n s o l u t e M s o l v e n t ( k g ) ]

    4 = ( 1 0 0 0 7 9 5 . 8 6 ) × 1 . 8 6 3 4 2 a        

    a = 0.2775kg or 277.5 gram

    Ice separated = (795.86 – 277.5) gram

    = 518.3 gram

    Ans. = 518 (the nearest integer)

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