10.0 mL of Na?CO? solution is titrated against 0.2 M HCl solution.
The following titre values were obtained in 5 readings:
4.8 mL, 4.9 mL 5.0 mL, 5.0 mL and 5.0 mL
Based on these readings, and convention of titrimetric estimation the concentration of Na?CO? solution is ________ mM. (Round off to the nearest integer).
10.0 mL of Na?CO? solution is titrated against 0.2 M HCl solution.
The following titre values were obtained in 5 readings:
4.8 mL, 4.9 mL 5.0 mL, 5.0 mL and 5.0 mL
Based on these readings, and convention of titrimetric estimation the concentration of Na?CO? solution is ________ mM. (Round off to the nearest integer).
V (Na? CO? ) = 10 mL
Volume of HCl used will be 5 mL (average of titre values)
Meq of HCl = meq of Na? CO?
(M * n-factor * V)HCl = (M * n-factor * V)Na? CO?
0.2 * 1 * 5 = M * 2*10
M= 0.05 M
M= 50 mM
Similar Questions for you
CH3COOH + NaOH → CH3COONa + H2O
ΔH = –50.6 kJ/mol
NaOH + SA [HCl] → NaCl + H2O
ΔH = –55.9 kJ/mol
the value of ΔH for ionisation of CH3COOH
⇒ ΔH = +55.9 – 50.6
5.3 kJ/mol
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Chemistry Some Basic Concepts of Chemistry 2025
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