10.14 A hydrocarbon C5H10 does not react with chlorine in dark but gives a single monochloro compound C5H9Cl in bright sunlight. Identify the hydrocarbon.

As per the molecular formula $C_5{H}_{10}$ , one thing can be confirmed; the hydrogen is either cycloalkane or it is an alkene. However, alkenes readily react with chlorine in even dark because of the double bond. Therefore, it is possible that the hydrocarbon is cycloalkane. 

Now, let us consider the reactivity. Cycloalkanes are the saturated hydrocarbons with no double bonds. These do not react with Chlore in dark because such a reaction needs UV light for initiating the process of free radical substitution. Haloalkane and Haloarenes NCERT solutions cover this as well as other questions in further detail.

In bright sunlight, the UV light star

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As per the molecular formula $C_5{H}_{10}$ , one thing can be confirmed; the hydrogen is either cycloalkane or it is an alkene. However, alkenes readily react with chlorine in even dark because of the double bond. Therefore, it is possible that the hydrocarbon is cycloalkane. 

Now, let us consider the reactivity. Cycloalkanes are the saturated hydrocarbons with no double bonds. These do not react with Chlore in dark because such a reaction needs UV light for initiating the process of free radical substitution. Haloalkane and Haloarenes NCERT solutions cover this as well as other questions in further detail.

In bright sunlight, the UV light starts free radical substitution reaction. In cyclopentane, the substitution will result in single monochloro product because all hydrogen atoms are equivalent in the molecule. Therefore, by replacing any hydrogen with chlorine atom will result again in the same product i.e. $C_5{H}_9\mathrm{Cl}.$ This confirms that the hydrocarbon is cyclopentane.

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<p>As per the molecular formula <span class="mathml" contenteditable="false"> <math > <msub><mi>C</mi><mn>5</mn></msub> <msub><mi>H</mi><mn>10</mn></msub> </math> </span>, one thing can be confirmed; <strong>the hydrogen is either cycloalkane or it is an alkene.</strong> However, alkenes readily react with chlorine in even dark because of the double bond. Therefore, it is possible that the hydrocarbon is cycloalkane.&nbsp;</p><p>Now, let us consider the reactivity. Cycloalkanes are the saturated hydrocarbons with no double bonds. These do not react with Chlore in dark because such a reaction needs UV light for initiating the process of free radical substitution. &lt;a href="https://www.shiksha.com/preparation/chemistry-ncert-solutions-class-12th-haloalkanes-and-haloarenes-4511-ns" target="_blank" rel="noopener"&gt;<em><strong>Haloalkane and Haloarenes NCERT solutions</strong></em>&lt;/a&gt; cover this as well as other questions in further detail.</p><p>In bright sunlight, the UV light starts free radical substitution reaction. In cyclopentane, the substitution will result in single monochloro product because all hydrogen atoms are equivalent in the molecule. Therefore, by replacing any hydrogen with chlorine atom will result again in the same product i.e. <span class="mathml" contenteditable="false"> <math > <msub><mi>C</mi><mn>5</mn></msub> <msub><mi>H</mi><mn>9</mn></msub> <mi>Cl</mi> <mo>.</mo> </math> </span><strong>This confirms that the hydrocarbon is cyclopentane.</strong></p><div><div><picture><source srcset="https://images.shiksha.com/mediadata/images/articles/1690438892phpkLXZwX_480x360.jpeg" media=" (max-width: 500px)"><img src="https://images.shiksha.com/mediadata/images/articles/1690438892phpkLXZwX.jpeg" alt="" width="499" height="107"></picture></div></div>

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