10.15 Write the isomers of the compound having formula C4H9Br.

Double bond equivalent is used to find the level of unsaturations present in an organic molecule.

DBE = C +1-H/2+X/2-N/2

Where C= number of carbon atoms present H=number of hydrogen atoms present N=number of nitrogen atoms present X=number of halogen atoms present Double bond equivalent (DBE) for C₄H₉Br

= 4+1-9/2+1/2

=0

So none of the isomers has a ring or unsaturation, so the isomers are positions or chain isomers as shown below in the table:

<p>Double bond equivalent is used to find the level of unsaturations present in an organic molecule.</p><p>DBE = C +1-H/2+X/2-N/2</p><p>Where C= number of carbon atoms present H=number of hydrogen atoms present N=number of nitrogen atoms present X=number of halogen atoms present Double bond equivalent (DBE) for C₄H₉Br</p><p>= 4+1-9/2+1/2</p><p>=0</p><p>So none of the isomers has a ring or unsaturation, so the isomers are positions or chain isomers as shown below in the table:</p><div><div><picture><source srcset="https://images.shiksha.com/mediadata/images/articles/1690438998php5pocHa_480x360.jpeg" media=" (max-width: 500px)"><img src="https://images.shiksha.com/mediadata/images/articles/1690438998php5pocHa.jpeg" alt="" width="319" height="260"></picture></div></div>

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