10.27. State as to why
(a) a solution of Na2CO3 is alkaline?
(b) alkali metals are prepared by electrolysis of their fused chlorides?
(c) sodium is found to be more useful than potassium?
10.27. State as to why
(a) a solution of Na2CO3 is alkaline?
(b) alkali metals are prepared by electrolysis of their fused chlorides?
(c) sodium is found to be more useful than potassium?
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1 Answer
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(a) Na2CO3 is a salt of a weak acid, carbonic acid (H2CO3) and a strong base NaOH. Thus, it undergoes hydrolysis to produce strong base NaOH and its aqueous solution isalkaline in nature.
Na2CO3 (s) + H2O (l) → 2NaOH(b) Because the discharge potential of alkali metals is much higher than that of hydrogen, therefore when the aqueous solution of any alkali metal chloride is subjected to electrolysis, H2, instead of the alkali metal, is produced at the cathode. Therefore, alkali metals are prepared by electrolysis of their fused chlorides.
(c) Since potassium is move reactive than sodium and it is found in nature to a less exte
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Li+ has the highest hydration enthalpy.
Hence it is most hydrated
Therefore, Correct order of hydrated radii is Cs+ < Rb+ < K+ < Na+ < Li+
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