10.28 p-Dichlorobenzene has higher m.p. than those of o- and m-isomers. Discuss.

p-Dichlorobenzene is more symmetrical than o-and m-isomers. Because it fits more closely and easily in the crystal lattice than o-and m-isomers. Therefore, more energy is required to break the crystal lattice of p-dichlorobenzene. Therefore, p-dichlorobenzene is symmetrical and has a higher melting point and lower solubility than o-and m-isomers due to strong force of attraction in crystal.

Therefore more energy required to break lattice and will not easily be soluble.

<p>p-Dichlorobenzene is more symmetrical than o-and m-isomers. Because it fits more closely and easily in the crystal lattice than o-and m-isomers. Therefore, more energy is required to break the crystal lattice of p-dichlorobenzene. Therefore, p-dichlorobenzene is symmetrical and has a higher melting point and lower solubility than o-and m-isomers due to strong force of attraction in crystal.</p><p>Therefore more energy required to break lattice and will not easily be soluble.</p><div><div><picture><source srcset="https://images.shiksha.com/mediadata/images/articles/1690445186phpEnxf72_480x360.jpeg" media=" (max-width: 500px)"><img src="https://images.shiksha.com/mediadata/images/articles/1690445186phpEnxf72.jpeg" alt="" width="" height=""></picture></div></div>

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