100 mL of Na3PO4 solution contains 3.45g of sodium. The molarity of the solution is_________ × 10-2 mol L-1, (Nearest integer)
[Atomic Masses - Na : 23.0u, O : 16.0 u, P : 31.0 u]
100 mL of Na3PO4 solution contains 3.45g of sodium. The molarity of the solution is_________ × 10-2 mol L-1, (Nearest integer)
[Atomic Masses - Na : 23.0u, O : 16.0 u, P : 31.0 u]
Asked by Shiksha User
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1 Answer
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23 × 3 gm of Na contained by 164 gm of Na3PO4
So, 3.45 gm of Na contained by
Therefore mole of Na3PO4=
Molarity =
= 50.0 × 10-2 M
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