100 mL of Na3PO4 solution contains 3.45g of sodium. The molarity of the solution is_________ * 10-2 mol L-1, (Nearest integer)

[Atomic Masses - Na : 23.0u, O : 16.0 u, P : 31.0 u]

10 Views|Posted 6 months ago
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6 months ago

23 * 3 gm of Na contained by 164 gm of Na3PO4

So, 3.45 gm of Na contained by ( 1 6 4 * 3 . 4 5 6 9 ) gm of Na3PO4

Therefore mole of Na3PO4= 1 6 4 * 3 . 4 5 6 9 * 1 6 4 = 0.05 mol

Molarity = 0 . 0 5 * 1 0 0 0 1 0 0 M = 0.5 M

= 50.0 * 10-2 M

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Chemistry Some Basic Concepts of Chemistry 2025

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