100 mL of Na3PO4 solution contains 3.45g of sodium. The molarity of the solution is_________ * 10-2 mol L-1, (Nearest integer)
[Atomic Masses - Na : 23.0u, O : 16.0 u, P : 31.0 u]
100 mL of Na3PO4 solution contains 3.45g of sodium. The molarity of the solution is_________ * 10-2 mol L-1, (Nearest integer)
[Atomic Masses - Na : 23.0u, O : 16.0 u, P : 31.0 u]
23 * 3 gm of Na contained by 164 gm of Na3PO4
So, 3.45 gm of Na contained by
Therefore mole of Na3PO4=
Molarity =
= 50.0 * 10-2 M
Similar Questions for you
CH3COOH + NaOH → CH3COONa + H2O
ΔH = –50.6 kJ/mol
NaOH + SA [HCl] → NaCl + H2O
ΔH = –55.9 kJ/mol
the value of ΔH for ionisation of CH3COOH
⇒ ΔH = +55.9 – 50.6
5.3 kJ/mol
Kindly consider the solution
Fact.
Kindly go through the solution
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else.
On Shiksha, get access to
Learn more about...

Chemistry Some Basic Concepts of Chemistry 2025
View Exam DetailsMost viewed information
SummaryDidn't find the answer you were looking for?
Search from Shiksha's 1 lakh+ Topics
Ask Current Students, Alumni & our Experts
Have a question related to your career & education?
See what others like you are asking & answering



