11.45 When 3-methylbutan-2-ol is treated with HBr, the following reaction takes place: Give a mechanism for this reaction. (Hint : The secondary carbocation formed in step II rearranges to a more stable tertiary carbocation by a hydride ion shift from 3rd carbon atom.

Give a mechanism for this reaction. (Hint : The secondary carbocation formed in step II rearranges to a more stable tertiary carbocation by a hydride ion shift from 3rd carbon atom.

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    Answered by

    alok kumar singh | Contributor-Level 10

    5 months ago
    11.45 
    The first step in the mechanism of the given reaction is protonation of the alcohol followed by loss of water to give a 20 carbocation.

    A

    The next step is a rearrangement of the 20 carbocations formed in the above step is less stable it rearranges by a 1,2-hydride shift to form more stable 3° carbocations.

    The last step of the reaction is the nucleophilic attack of Br- ion on the 3° carbocations giving the final product.

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