11.66 Show how will you synthesise: (i) 1-phenylethanol from a suitable alkene. (ii) Cyclohexylmethanol using an alkyl halide by an SN2 reaction. (iii) Pentan-1-ol using a suitable alkyl halide?

<p><strong>11.66&nbsp;</strong></p><p><strong>1.&nbsp;</strong>1-phenylethanol from a suitable&nbsp; - The addition of water takes place according to Markovnikov rule. The alkene taken is styrene. And According to the rule, the positive charge i.e. H⁺ goes to the carbon of the double bond which has more number of hydrogens and the negative part i.e. OH- goes to the carbon that has less number of hydrogens. Therefore resulting the final product as 1-phenyl ethanol.</p><p><strong>2. </strong>In the above conversion, NaOH gets dissociated into Na⁺ and OH^-and Na⁺ then combines with Cl of chloromethylcyclohexane forming NaCl and thus the final product Cyclohexylmethanol is obtained.</p><p><strong>3. </strong>In this conversion also, Na forms the compound with Cl i.e. NaCl and to compensate the negative charge formed by Cl, OH attacks at that position resulting in pentan-1-ol.</p>

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