116 g of a substance upon dissociation reaction yields 7.5 g of hydrogen 60 g of oxygen and 48.5 g of carbon. Given that the atomic masses of H, O and C are 1, 16 and 12, respectively. The data agrees with how many formulae of the following?

(a) CH3COOH                                  (b) HCHO                          (c) CH3OOCH3                            (d) CH3CHO

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7 months ago

Determining empirical formula of the given compound.

% o f C = 4 8 . 5 1 1 6 * 1 0 0 % = 4 1 . 8 %               

% o f H = 7 . 5 1 1 6 * 1 0 0 % = 6 . 5 %               

% o f O = 6 0 1 1 6 * 1 0 0 % = 5 1 . 7 %               

              Mass         Moles                  Simplest ratio

C            41.8g        4 1 . 8 1 2 = 3 . 4 8         3 . 4 8 3 . 2 3 1                 

H            6.5 g        6 . 5 1 = 6 . 5             6 . 5 3 . 2 3 2                      

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 CH4+2O2CO2+2H2O

Mole 1001620832

6.256.5 (HereO2isthelimitingreagent)

Hence mole of CO2 formed = 6.52

And wt of CO2  in gm = 6.52×44=143g

In 4d orbital, n = 4 and l=2

Radial nodes = nl1

Radial nodes = 4 – 2 – 1 = 1

And angular nodes,  l=2

 Molality=molesofsolute×1000wtofsolvent (gm)

Molality=35×1000×1.4636.5×100 = 14.0 M

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Chemistry NCERT Exemplar Solutions Class 12th Chapter Eight 2025

Chemistry NCERT Exemplar Solutions Class 12th Chapter Eight 2025

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