13.10 Write IUPAC names of the following compounds and classify them into primary, secondary and tertiary amines.

(i) (CH₃ ) ₂CHNH₂

(ii) CH₃ (CH₂ ) ₂NH₂

(iii) CH₃NHCH(CH₃ ) ₂

(iv) (CH₃ ) ₃CNH₂

(v) C₆H₅NHCH₃

(vi) (CH₃CH₂ ) ₂NCH₃

 (vii) M–BrC₆H₄NH₂

<p><strong>1 - Methylethanamine</strong></p><p>The root name is based on the longest chain with the -NH₂ attached. The chain is numbered so as to give the amine unit the lowest possible number. The longest chain is ethane chain which is further suffixed with ‘amine’.</p><p><strong>2 - Propan-1-amine</strong></p><p>The longest chain here is propane. The naming is such that amine unit should get a the lowest possible number. Propane-1-amine can also be written as 1-propylamine.</p><p><strong>3 - N−Methyl-2-methylethanamine</strong></p><p>The chain is numbered so as to give the amine unit the lowest possible number. The other alkyl group is treated as a substituent, with N as the locant. The N locant is listed before numerical locants. The longest chain is ethane which has a Methyl substituent group.</p><p><strong>4 - 2-Methylpropan-2-amine</strong></p><p>Propane is the longest chain and is joined to the amine group at the 2^nd position. Another substituent methyl group is also at the same position.</p><p><strong>5 - N−Methylbenzamine or N-methylaniline</strong></p><p>Aniline is considered as the principle group. The other alkyl group is treated as a substituent, with N as the locant.</p><p><strong>6 - N-Ethyl-N-methylethanamine</strong></p><p>This is a tertiary group of amine. The root name is based on the longest chain with an amine having the lowest possible number. The alkyl groups are treated as substituents with N as the locant.</p><p><strong>7 - 3-Bromobenzenamine or 3-bromoaniline</strong></p><p>Benzene is considered as the principle group. The substituent is bromine which is numbered 3.</p>

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