13.20 Complete the following reactions:

(i) C₆H₅NH₂ + CH₃Cl + KOH →

(ii) C₆H₅N₂Cl + H₃PO₂ + H₂O →

(iii) C₆H₅NH₂ + H₂SO₄ (conc) →

(iv) C₆H₅N₂Cl + C₂H₅OH à

(v) C₆H₅NH₂ + Br₂ (aq) à

(vi) C₆H₅NH₂ + (CH₃CO)₂O à

(vii) C₆H₅N₂Cl

<p><strong>1- </strong>C₆H₅NH₂ + CHCl₃ + KOH</p><p>It is a carbylamine reaction in which a isocyanide compound is formed along with side products of potassium chloride.Basically the name of reaction is given is due to formation of a foul smelling compound called as isocyanide.</p><p><strong>2- </strong>C₆H₅N₂Cl + H₃PO₂ + H₂O</p><p>Benzenediazonium chloride is a very reactive compound which oxidises hypophosphorous acid to hypophosphoric acid and the reactant is reduced to benzene.</p><p><strong>3- </strong>C₆H₅NH₂ + H₂SO₄ (conc.)</p><p>Aniline undergoes sulphonation to anillium hydrogensulphate.</p><p><strong>4- </strong>C₆H₅N₂Cl + C₂H₅OH</p><p>Aniline is very activating group which undergoes reaction to give ortho and para product. But in acidic medium aniline accquires positive charge on N atom which is metadirecting group and hence the product.</p><p><strong>5- </strong>C₆H₅NH₂ + Br₂ (aq)</p><p>It is clubbing reaction of a very reactive compound undergoing addition to give benzene.</p><p><strong>6- </strong>C₆H₅NH₂ + (CH₃CO)₂O</p><p>As mentioned aniline is avery activating group, so to reduce its activity it is reacted with anhydride to give n-phenylethanamine.</p><p><strong>7- </strong>C₆H₅N₂Cl</p><p>Hydrofluroburic acid reacts qith benzenediazonium chloride along with sodium nitrite to give a reduced product as Nitrobenzene.</p>

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