13.20 Complete the following reactions: (i) C6H5NH2 + CH3Cl + KOH → (ii) C6H5N2Cl + H3PO2 + H2O → (iii) C6H5NH2 + H2SO4 (conc) → (iv) C6H5N2Cl + C2H5OH à (v) C6H5NH2 + Br2 (aq) à (vi) C6H5NH2 + (CH3CO)2O à (vii) C6H5N2Cl

1- C6H5NH2 + CHCl3 + KOH It is a carbylamine reaction in which a isocyanide compound is formed along with side products of potassium chloride.Basically the name of reaction is given is due to formation of a foul smelling compound called as isocyanide. 2- C6H5N2Cl + H3PO2 + H2O Benzenediazonium chloride is a very reactive compound which oxidises hypophosphorous acid to hypophosphoric acid and the reactant is reduced to benzene. 3- C6H5NH2 + H2SO4 (conc.) Aniline undergoes sulphonation to anillium hydrogensulphate. 4- C6H5N2Cl + C2H5OH Aniline is very activating group which undergoes reaction to give ortho and para product. But in acidic medium aniline accquires positive charge on N atom which is metadirecting group and hence the product. 5- C6H5NH2 + Br2 (aq) It is clubbing reaction of a very reactive compound undergoing addition to give benzene. 6- C6H5NH2 + (CH3CO)2O As mentioned aniline is avery activating group, so to reduce its activity it is reacted with anhydride to give n-phenylethanamine. 7- C6H5N2Cl Hydrofluroburic acid reacts qith benzenediazonium chloride along with sodium nitrite to give a reduced product as Nitrobenzene.

13.20 Complete the following reactions:

(i) C₆H₅NH₂ + CH₃Cl + KOH →

(ii) C₆H₅N₂Cl + H₃PO₂ + H₂O →

(iii) C₆H₅NH₂ + H₂SO₄ (conc) →

(iv) C₆H₅N₂Cl + C₂H₅OH à

(v) C₆H₅NH₂ + Br₂ (aq) à

(vi) C₆H₅NH₂ + (CH₃CO)₂O à

(vii) C₆H₅N₂Cl

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Vishal Baghel | Contributor-Level 10

8 months ago

1- C₆H₅NH₂ + CHCl₃ + KOH

It is a carbylamine reaction in which a isocyanide compound is formed along with side products of potassium chloride.Basically the name of reaction is given is due to formation of a foul smelling compound called as isocyanide.

2- C₆H₅N₂Cl + H₃PO₂ + H₂O

Benzenediazonium chloride