13.4 Arrange the following in increasing order of their basic strength:
(i) C2H5NH2, C6H5NH2, NH3, C6H5CH2NH2 and (C2H5)2NH
(ii) C2H5NH2, (C2H5 )2NH, (C2H5 )3N, C6H5NH2
(iii) CH3NH2, (CH3 )2NH, (CH3)3N, C6H5NH2, C6H5CH2 NH2 .
13.4 Arrange the following in increasing order of their basic strength:
(i) C2H5NH2, C6H5NH2, NH3, C6H5CH2NH2 and (C2H5)2NH
(ii) C2H5NH2, (C2H5 )2NH, (C2H5 )3N, C6H5NH2
(iii) CH3NH2, (CH3 )2NH, (CH3)3N, C6H5NH2, C6H5CH2 NH2 .
1- Alkyl group contribute inductive effect which increases the basic strength of
NH3
Then C6H5NH2 is having –I effect that reduces strength. And C6H5CH2NH2 increases the basic strength but not as much as C2H5 group.
Hence final order will be C6H5NH2<
2- By taking into consideration –R effect and s
Similar Questions for you
In Amines, the nitrogen atom bonds with alkyl or aryl groups replacing hydrogen, whereas in amides, the nitrogen atom bonds directly with the carbonyl group (-CO-).
Kjeldahl's method is not applicable to compounds containing nitrogen in nitro and azo groups and nitrogen present in the ring.
Correct order of basic strength in aqueous medium is
Kindly consider the following figure
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