1L aqueous solution of H2SO4 contains 0.02m mol H2SO4. 50% of this solution is dilutd with deionized water to give 1L solution (A). In solution (A), 0.01m mol of H2SO4 are added. Total m mols of H2SO4 in the final solution is ________* 103 m mols

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6 months ago

1000 ml solution contains 0.02 milli mole (mm)

500 ml solution contains 0.02 m.m

Solution made 1000 ml with H2O

m.m in final solution = 0.01 mm

Solution (A) + 0.01 m. m H2SO4

= 0.01 + 0.01

= 0.02 m.m

= 0.00002 * 103 mm

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Chemistry NCERT Exemplar Solutions Class 12th Chapter Twelve 2025

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