1L aqueous solution of H2SO4 contains 0.02m mol H2SO4. 50% of this solution is dilutd with deionized water to give 1L solution (A). In solution (A), 0.01m mol of H2SO4 are added. Total m mols of H2SO4 in the final solution is ________* 103 m mols
1L aqueous solution of H2SO4 contains 0.02m mol H2SO4. 50% of this solution is dilutd with deionized water to give 1L solution (A). In solution (A), 0.01m mol of H2SO4 are added. Total m mols of H2SO4 in the final solution is ________* 103 m mols
1000 ml solution contains 0.02 milli mole (mm)
500 ml solution contains 0.02 m.m
Solution made 1000 ml with H2O
m.m in final solution = 0.01 mm
Solution (A) + 0.01 m. m H2SO4
= 0.01 + 0.01
= 0.02 m.m
= 0.00002 * 103 mm
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CH3COOH + NaOH → CH3COONa + H2O
ΔH = –50.6 kJ/mol
NaOH + SA [HCl] → NaCl + H2O
ΔH = –55.9 kJ/mol
the value of ΔH for ionisation of CH3COOH
⇒ ΔH = +55.9 – 50.6
5.3 kJ/mol
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Chemistry NCERT Exemplar Solutions Class 12th Chapter Twelve 2025
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