1L aqueous solution of H2SO4 contains 0.02m mol H2SO4. 50% of this solution is dilutd with deionized water to give 1L solution (A). In solution (A), 0.01m mol of H2SO4 are added. Total m mols of H2SO4 in the final solution is ________× 103 m mols
1L aqueous solution of H2SO4 contains 0.02m mol H2SO4. 50% of this solution is dilutd with deionized water to give 1L solution (A). In solution (A), 0.01m mol of H2SO4 are added. Total m mols of H2SO4 in the final solution is ________× 103 m mols
-
1 Answer
-
1000 ml solution contains 0.02 milli mole (mm)
500 ml solution contains 0.02 m.m
Solution made 1000 ml with H2O
m.m in final solution = 0.01 mm
Solution (A) + 0.01 m. m H2SO4
= 0.01 + 0.01
= 0.02 m.m
= 0.00002 × 103 mm
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else
Sign Up on ShikshaOn Shiksha, get access to
- 65k Colleges
- 1.2k Exams
- 687k Reviews
- 1800k Answers