2.5g protein containing only glycine (C2H5NO2) is dissolved in water to make 500 mL of solution. TH osmotic pressure of this solution at 300 K is found to be 5.03 * 10-3 bar. The total number of glycine units present in the protein is___________.

(Given : R = 0.083 L bar K-1 mol-1)

3 Views|Posted 8 months ago
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8 months ago

π = n v R T

π = W M * v R T

5 . 0 3 * 1 0 3 = 2 . 5 M * 0 . 5 * 0 . 0 8 3 * 3 0 0

M = 2 . 5 * 0 . 0 8 3 * 3 0 0 5 . 0 3 * 0 . 5 * 1 0 3 g / m o l

Molar mass of protein, M = 24751 g/mol

 Molar mass of glycine = 75 g/mol

So; number of glycine units =   2 4 7 5 1 7 5 = 3 3 0

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Chemistry NCERT Exemplar Solutions Class 12th Chapter Three 2025

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