20 mL of 0.02 M K2Cr2O7 solution is used for the titraction of 10 mL of Fe2+ solution in the acidic medium. The molarity of Fe2+ solution is ___________* 10-2 M. (Nearest Integer)
20 mL of 0.02 M K2Cr2O7 solution is used for the titraction of 10 mL of Fe2+ solution in the acidic medium. The molarity of Fe2+ solution is ___________* 10-2 M. (Nearest Integer)
Meq of K2Cr2O7 = Meq of Fe2+
-> (Molarity * Volume * nf) of K2Cr2O7 = (molarity * volume * nf) of Fe2+
->0.02 * 20 * 6 = M * 10 * 1
M = 0.24 M
Molarity = 24 * 10-2 M
Upvote 
Similar Questions for you
ΔG° = –RT * 2.303 log K
–nFE° = +RT * 2.303 log K
2 * 96500 * 0.295 = 8.314 * 298 * 2.303 log10 K
10 = log10 K = 1010
It has chiral centre and differently di substituted double bonded carbon atoms.
Rate of ESR ∝ No. of α – H (Hyperconjugation)
Cr3+ion is a most stable in aqueous solution due to. t2g half filled configuration
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else.
On Shiksha, get access to
Learn more about...
Chemistry Ncert Solutions Class 12th 2023
View Exam DetailsMost viewed information
SummaryDidn't find the answer you were looking for?
Search from Shiksha's 1 lakh+ Topics
Ask Current Students, Alumni & our Experts
Have a question related to your career & education?
See what others like you are asking & answering