200mL of 0.01 M HCl is mixed with 400mL of 0.01 M H2SO4. The pH of the mixture is___________.

Given: log2 = 0.30, log 3 = 0.48, log5 = 0.70, log7 = 0.84, log11 = 1.04

Option 1 - <p>1.14&nbsp;</p>
Option 2 - <p>1.78&nbsp;&nbsp;</p>
Option 3 - <p>2.34&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</p>
Option 4 - <p>3.02</p>
15 Views|Posted 7 months ago
Asked by Shiksha User
1 Answer
P
7 months ago
Correct Option - 2
Detailed Solution:

Total concentration of H+ after the mixing of HCl and H2SO4;

[H+]= (200*0.01)+ (400*2*0.01)600

[H+]=160

pH=log10 (160)=1.78

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Chemistry Ncert Solutions Class 11th 2023

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