21. Comment on the thermodynamic stability of NO (g), given
½ N2 (g) + ½ O2 (g) → NO (g); ΔrH? = 90 kJ mol–1
NO (g) + ½ O2 (g) → NO2 (g); ΔrH? = –74 kJ mol–1
21. Comment on the thermodynamic stability of NO (g), given
½ N2 (g) + ½ O2 (g) → NO (g); ΔrH? = 90 kJ mol–1
NO (g) + ½ O2 (g) → NO2 (g); ΔrH? = –74 kJ mol–1
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1 Answer
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21. For NO (g), ΔrH° is a +ve value. So, it is unstable in nature.
For NO2 (g), ΔrH° is a -ve value. So, it is stable
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