250 mL of 0.5 M NaOH was added to 500 mL of 1 M HCl. The number of unreacted HCl molecules in the solution after complete reaction is_________ × 10²¹ (Nearest integer)

(N_A = 6.022 ×10²³)

4 Views | Posted 3 months ago

Asked by Shiksha User

1 Answer

Answered by

alok kumar singh | Contributor-Level 10

3 months ago

NaOH + HCl -> NaCl + H₂O

(milimole) t = 0 250 × 0.5 500 × 1.0 0 0

t = $\infty$ - 375 125

...more

NaOH + HCl -> NaCl + H₂O

(milimole) t = 0 250 × 0.5 500 × 1.0 0 0

t = $\infty$ - 375 125 125 millimole

unreacted HCl mole = $\frac{375}{1000}$

number of HCl molecule unreacted = $\frac{375}{1000} \times 6.023 \times 1 0^{23}$

= 225.75 × 10²¹ $\approx$ 226 × 10²¹

less

NaOH      +      HCl   ->  NaCl     +      H2O (milimole) t = 0                250 × 0.5     500 × 1.0     0            0            t = <!- [if gte mso 9]><xml> <o:OLEObject Type="Embed" ProgID="Equation.DSMT4" ShapeID="_x0000_i1025" DrawAspect="Content" ObjectID="_1816170950"> </o:OLEObject></xml><! [endif]->  <math> <mrow> <mo>∞</mo> </mrow> </math>      -         375        125        125 millimoleunreacted HCl mole = <math> <mrow> <mfrac> <mrow> <mn>3</mn> <mn>7</mn> <mn>5</mn> </mrow> <mrow> <mn>1</mn> <mn>0</mn> <mn>0</mn> <mn>0</mn> </mrow> </mfrac> </mrow> </math>  <!- [if gte mso 9]><xml> <o:OLEObject Type="Embed" ProgID="Equation.DSMT4" ShapeID="_x0000_i1026" DrawAspect="Content" ObjectID="_1816170951"> </o:OLEObject></xml><! [endif]->number of HCl molecule unreacted = <math> <mrow> <mfrac> <mrow> <mn>3</mn> <mn>7</mn> <mn>5</mn> </mrow> <mrow> <mn>1</mn> <mn>0</mn> <mn>0</mn> <mn>0</mn> </mrow> </mfrac> <mo>×</mo> <mn>6</mn> <mo>.</mo> <mn>0</mn> <mn>2</mn> <mn>3</mn> <mo>×</mo> <mn>1</mn> <msup> <mrow> <mn>0</mn> </mrow> <mrow> <mn>2</mn> <mn>3</mn> </mrow> </msup> </mrow> </math>  <!- [if gte mso 9]><xml> <o:OLEObject Type="Embed" ProgID="Equation.DSMT4" ShapeID="_x0000_i1027" DrawAspect="Content" ObjectID="_1816170952"> </o:OLEObject></xml><! [endif]->= 225.75 × 1021 <math> <mrow> <mo>≈</mo> </mrow> </math> <!- [if gte mso 9]><xml> <o:OLEObject Type="Embed" ProgID="Equation.DSMT4" ShapeID="_x0000_i1028" DrawAspect="Content" ObjectID="_1816170953"> </o:OLEObject></xml><! [endif]->226 × 1021

0 Upvotes 0 Downvotes

Get authentic answers from experts, students and alumni that you won't find anywhere else

On Shiksha, get access to

65k Colleges
1.2k Exams
679k Reviews
1800k Answers

Community GuidelinesUser Points System

QuestionsDiscussionsTags

250 mL of 0.5 M NaOH was added to 500 mL of 1 M HCl. The number of unreacted HCl molecules in the solution after complete reaction is_________ × 10²¹ (Nearest integer)

(N_A = 6.022 ×10²³)

1 Answer

Learn more about...

Most viewed information

Share Your College Life Experience

Didn't find the answer you were looking for?

Need guidance on career and education? Ask our experts

Your Question

250 mL of 0.5 M NaOH was added to 500 mL of 1 M HCl. The number of unreacted HCl molecules in the solution after complete reaction is_________ × 1021 (Nearest integer) (NA = 6.022 ×1023)

1 Answer

Learn more about...

Most viewed information

Share Your College Life Experience

Didn't find the answer you were looking for?

Need guidance on career and education? Ask our experts

Your Question

250 mL of 0.5 M NaOH was added to 500 mL of 1 M HCl. The number of unreacted HCl molecules in the solution after complete reaction is_________ × 10²¹ (Nearest integer)

(N_A = 6.022 ×10²³)