250 mL of a waste solution obtained from the workshop of a goldsmith contains 0.1M AgNO3 and 0.1M AuCl. The solution was electrolyzed at 2 V by passing a current of 1 A for 15 minutes. The metal/metals electrodeposited will be : (E°Ag+/Ag = 0.8 V, E°Au+/Au = 1.69 V)
250 mL of a waste solution obtained from the workshop of a goldsmith contains 0.1M AgNO3 and 0.1M AuCl. The solution was electrolyzed at 2 V by passing a current of 1 A for 15 minutes. The metal/metals electrodeposited will be : (E°Ag+/Ag = 0.8 V, E°Au+/Au = 1.69 V)
Option 1 -
Silver and gold in equal mass proportion
Option 2 -
Only silver
Option 3 -
Only gold
Option 4 -
Silver and gold in proportion to their atomic weights
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1 Answer
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Correct Option - 3
Detailed Solution:Charge (q) = (it/96500) F = (1x15x60)/96500 = 900/96500 = 9/965 F = 0.0093F
No. of moles of Au? = 0.025 & No. of moles of Ag? = 0.025
Species with higher value of SRP will get deposited first at cathode.
(i) Au? (aqs) + e? → Au (s)
0.025 0.0093 mole
So only Au will get deposited
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