4.25. Describe the change in hybridisation (if any) of the Al atom in the following reaction.
AlCl3 + Cl– ——> AlCl4-
4.25. Describe the change in hybridisation (if any) of the Al atom in the following reaction.
AlCl3 + Cl– ——> AlCl4-
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1 Answer
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4.25. Electronic configuration of 13Al in ground state= 1s2 2s2 2p6 3s2 3p1
Electronic configuration of 13Al in excited state = 1s2 2s2 2p6 3s1 3px13py1
Hence, hybridisation will be sp2 and this makes the geometry to be Trigonal planar (in case of AlCl3).
In AlCl–4, the empty 3pz orbital is also involved. So, the hybridisation is sp3 and the shape is tetrahedral
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